	案例SS	案例CS
q₁₁	$\frac{2 [m (2 + n) (n - 4) - 2 n]}{(4 - n^{2}) (16 - n^{2})}$	$\frac{m (n + 1) (8 - 4 n - n^{2}) - n (4 - n^{2})}{2 (1 - n^{2}) (16 - 7 n^{2})}$
q₁₁
q₁₂	0	0
q₂₁	0	$\frac{{(4 - n^{2})}^{2} - m (1 + n) (2 n + 16 - 10 n^{2} + n^{3})}{6 (1 - n^{2}) (16 - 7 n^{2})}$
q₂₂	$\frac{2 [8 - n^{2} - m (2 + n) (n - 4)]}{(4 - n^{2}) (16 - n^{2})}$	$\frac{2 (4 - n^{2}) - m (8 - 3 n - 2 n^{2})}{48 - 21 n^{2}}$
w₁	$\frac{m (2 + n) (4 - n) - 2 n}{16 - n^{2}}$	$\frac{m (n + 1) (8 - 4 n - n^{2}) - n (4 - n^{2})}{16 - 7 n^{2}}$
w₂	$\frac{8 - n^{2} - m (n + 2) (4 - n)}{16 - n^{2}}$	$\frac{8 - 5 n^{2} - m (n + 1) (8 - 5 n)}{16 - 7 n^{2}}$