阶数

Cobb-Douglas函数

n = 0

f ( x ) = e a x 1 b x 2 c x 3 1 b c

(3)

n = 1

f ( x ) = e a t + b x 1 c x 2 d x 3 1 c d

(4)

n = 2

f ( x ) = e a t 2 + b t + c x 1 d x 2 e x 3 1 d e

(5)

n = 3

f ( x ) = e a t 3 + b t 2 + c t + d x 1 e x 2 f x 3 1 e f

(6)

n = 4

f ( x ) = e a t 4 + b t 3 + c t 2 + d t + e x 1 f x 2 g x 3 1 f g

(7)

n = 5

f ( x ) = e a t 5 + b t 4 + c t 3 + d t 2 + e t + f x 1 g x 2 h x 3 1 g h

(8)