阶数
Cobb-Douglas函数
n = 0
f ( x ) = e a x 1 b x 2 c x 3 1 − b − c
(3)
n = 1
f ( x ) = e a t + b x 1 c x 2 d x 3 1 − c − d
(4)
n = 2
f ( x ) = e a t 2 + b t + c x 1 d x 2 e x 3 1 − d − e
(5)
n = 3
f ( x ) = e a t 3 + b t 2 + c t + d x 1 e x 2 f x 3 1 − e − f
(6)
n = 4
f ( x ) = e a t 4 + b t 3 + c t 2 + d t + e x 1 f x 2 g x 3 1 − f − g
(7)
n = 5
f ( x ) = e a t 5 + b t 4 + c t 3 + d t 2 + e t + f x 1 g x 2 h x 3 1 − g − h
(8)