	案例SS	案例CS
q₁₁	0	$\frac{m n (n + 1) (2 n + 4 - 3 n^{2}) - n (4 - n^{2})}{6 (1 - n^{2}) (2 - n^{2}) (4 - n^{2})}$
q₁₂	－	－
q₂₁	－	$\frac{(4 - n^{2}) (n^{4} + 6 - 4 n^{2}) - m (n + 1) [24 - n (12 + 10 n + 2 n^{2} + 4 n^{3})]}{6 (1 - n^{2}) (2 - n^{2}) (4 - n^{2})}$
q₂₂	$\frac{2 (2 - n) (n + 2) - 2 m (2 n + 4 - n^{2})}{32 - 16 n^{2} + n^{4}}$	$\frac{(4 - m^{2}) (6 - n^{2}) - m [24 + n (n + 2) (6 - 8 n + n^{2})]}{18 (2 - n^{2}) (4 - n^{2})}$
d₁	$\frac{2 m (4 - n) (n + 2) - 4 n}{32 - 16 n^{2} + n^{4}}$	$\frac{m (4 + 4 n - 12 n^{2} - n^{3}) - n (4 - n^{2})}{6 (2 - n^{2}) (4 - n^{2})}$
w₁	$\frac{m (8 + 2 n - n^{2}) (2 - n^{2}) - 2 n (2 - n^{2})}{32 - 16 n^{2} + n^{4}}$	$\frac{m (24 + 12 n - 24 n^{2} - 7 n^{3} + 6 n^{4} + n^{5}) - n (3 - n^{2}) (4 - n^{2})}{6 (2 - n^{2}) (4 - n^{2})}$
w₂	$\frac{{(4 - n^{2})}^{2} - m (2 n + 4 - n^{2}) (4 - n^{2})}{32 - 16 n^{2} + n^{4}}$	$\frac{(3 - 2 n^{2}) (4 - n^{2}) - m (n + 1) (12 - 6 n - 5 n^{2} + 2 n^{3})}{3 (2 - n^{2}) (4 - n^{2})}$