	案例SS	案例CS
q₁₁	$\frac{2 m (2 n + 4 - n^{2}) - 4 n}{32 - 16 n^{2} + n^{4}}$	$\frac{m (n + 1) (8 - 4 n - n^{2}) - n (2 - n) (n + 2)}{2 (1 - n^{2}) (16 - 7 n^{2})}$
q₁₂	－	－
q₂₁	－	$\frac{n [(5 - 2 n) - m (n + 1) (n + 2) (2 n - 3)]}{2 (1 - n^{2}) (16 - 7 n^{2})}$
q₂₂	0	$\frac{n [m (2 - n) + n]}{2 (16 - 7 n^{2})}$
d₂	$\frac{2 (8 - n^{2}) - 2 m (n + 2) (4 - n)}{32 - 16 n^{2} + n^{4}}$	$\frac{1 - m}{2}$
w₁	$\frac{(4 - n^{2}) [m (2 n + 4 - n^{2}) - 2 n]}{32 - 16 n^{2} + n^{4}}$	$\frac{m (n + 1) (8 - 4 n - n^{2}) - n (4 - n^{2})}{16 - 7 n^{2}}$
w₂	$\frac{(2 - n^{2}) [8 - n^{2} - m (n + 2) (4 - n)]}{32 - 16 n^{2} + n^{4}}$	$\frac{8 - 5 n^{2} - m (n + 1) (8 - 5 n)}{16 - 7 n^{2}}$