	案例SS	案例CS
q₁₁	0	$\frac{n^{2} [m (n + 1) (n + 2) (8 - 5 n) - n (5 n^{2} - 14)]}{2 (1 - n^{2}) (96 - 88 n^{2} + 19 n^{4})}$
q₁₂	—	—
q₂₁	—	$\frac{n^{2} [12 - 2 n^{2} - n^{4} - m (n + 1) (12 + 6 n)]}{2 (1 - n^{2}) (96 - 88 n^{2} + 19 n^{4})}$
q₂₂	0	$\frac{n^{2} [2 (3 - n^{2}) - m (2 - n) (2 n + 3)]}{96 - 88 n^{2} + 19 n^{4}}$
d₁	$\frac{2 [m (4 + 2 n - n^{2}) - 2 n]}{4 - {(2 n - n^{2})}^{2}}$	$\frac{3 [m (16 + 8 n - 8 n^{2} - 3 n^{3}) - n (8 - 3 n^{2})]}{96 - 88 n^{2} + 19 n^{4}}$
d₂	$\frac{2 [4 - n^{2} - m (4 + 2 n - n^{2})]}{4 - {(2 n - n^{2})}^{2}}$	$\frac{(4 - n^{2}) (12 - 5 n^{2}) - m (48 + 24 n - 32 n^{2} - 12 n^{3})}{96 - 88 n^{2} + 19 n^{4}}$
w₁	$\frac{(2 - n^{2}) [m (4 + 2 n - n^{2}) - 2 n]}{4 - {(2 n - n^{2})}^{2}}$	$\frac{m (n + 1) (48 - 24 n - 32 n^{2} + 13 n^{3} + 4 n^{4})}{96 - 88 n^{2} + 19 n^{4}}$
w₂	$\frac{(2 - n^{2}) [4 - n^{2} - m (2 n + 4)]}{4 - {(2 n - n^{2})}^{2}}$	$\frac{48 - 50 n^{2} + 11 n^{4} - m (48 - 24 n - 26 n^{2} + 11 n^{3})}{96 - 88 n^{2} + 19 n^{4}}$