单分量情形

双分量情形

模型解

${\begin{cases} 2 | [(h_{1} - 1) τ + 1] | > | (h_{1} + 1) | \\ | b [(h_{1} - 1) τ + 1] | > 1 \end{cases}$

${\begin{cases} 2 [| ({\hat{h}}_{1} - 1) τ + 1 | + | ({\tilde{h}}_{1} - 1) τ + 1 |] > [| ({\hat{h}}_{1} + 1) | + | ({\tilde{h}}_{1} + 1) |] \\ | b | [| ({\hat{h}}_{1} - 1) τ + 1 | + | ({\tilde{h}}_{1} - 1) τ + 1 |] > 2 \end{cases}$

参数约束

$a_{1} + 2 b_{1} β \neq 0$

$\frac{d_{1} - h_{1}}{2 b_{1}} τ^{2} - β {(1 - τ)}^{2} + \frac{a}{2 b} = 0$

$a_{1} + 2 b_{1} \hat{β} \neq 0, a_{1} + 2 b_{1} \tilde{β} \neq 0$

$\frac{d_{1} - {\hat{h}}_{1}}{2 b_{1}} τ^{2} - \hat{β} {(1 - τ)}^{2} + \frac{a}{2 b} = 0$

$\frac{d_{1} - {\tilde{h}}_{1}}{2 b_{1}} τ^{2} - \tilde{β} {(1 - τ)}^{2} + \frac{a}{2 b} = 0$