4

$\begin{array}{l}{x}^6-p_5\cdot x^5+p_4\cdot x^4+{\left[p\right]}_3\cdot x^3-p_2\cdot x^2+{\left[p\right]}_1\cdot x+{\left[p\right]}_0,{\left[p\right]}_0=16.1024,\\ {\left[p\right]}_1=\left[15.8448,16.52\right],p_2=7.872,{\left[p\right]}_3=\left[-4.0388,-3.875\right],p_4=1.0256,p_5=2\end{array}$

5

$\begin{array}{l}{x}^4+{\left[p\right]}_1^3\cdot {\left[p\right]}_2\cdot x^3+{\left[p\right]}_1^2\cdot {\left[p\right]}_2^2\cdot {\left[p\right]}_3\cdot x^2+{\left[p\right]}_1\cdot {\left[p\right]}_2^3\cdot {\left[p\right]}_3^2\cdot x^2+{\left[p\right]}_3,\\ {\left[p\right]}_1=\left[1.15,1.65\right],{\left[p\right]}_2=\left[1.3,1.7\right],{\left[p\right]}_3=\left[0.6,1.0\right]\end{array}$

6

$\begin{array}{l}\left[{\left(x+10\cdot {\left[p\right]}_0\right)}^2-5\cdot {\left(x-{\left[p\right]}_1\right)}^2-{\left(x-2{\left[p\right]}_2\right)}^4\right]\cdot {\text{e}}^{-x^2}+2,\\ {\left[p\right]}_0=\left[-1,0\right],{\left[p\right]}_1=\left[0,0.5\right],{\left[p\right]}_2=\left[-0.25,0.25\right]\end{array}$

7

$y={\left(\frac{5}{\pi }\cdot x-\left(\frac{5.1}{4\cdot {\pi }^2}\right)\cdot x^2+a-6\right)}^2+10\cdot \frac{1}{1-\frac{1}{8\pi }}\cdot \cos \left(x\right),\left[p\right]=\left[-2,0\right]$

8

${\displaystyle \sum }_{j=1}^5\left\{j\cdot \sin \left(\left(j+1\right)\cdot \left[p\right]+j\right)\right\}\cdot {\displaystyle \sum }_{i=1}^5\left\{i\cdot \sin \left(\left(i+1\right)\cdot x+i\right)\right\}-10,\left[p\right]=\left[-0.1,0.2\right]$

9

${\displaystyle \sum }_{j=1}^{5}j\cdot \left[\sin \left(\left(j+1\right)\cdot x+j\right)+x\cdot \sin \left(\left(j+1\right)\cdot \left[p\right]+j\right)\right],p=\left[-0.1,0.2\right]$

10

$100\cdot {\left(\left[p\right]-x^2\right)}^2+{\left(x-1\right)}^2,p=\left[-5,5\right]$

11

${\displaystyle \sum }_{\begin{array}{l}i=1\\ i\ne 4\end{array}}^7\frac{{\left[p\right]}_i^2}{4000}+\frac{x^2}{4000}-\left({\displaystyle \prod }_{\begin{array}{l}i=1\\ i\ne 4\end{array}}^7\cos \left(\frac{{\left[p\right]}_i}{\sqrt{i}}\right)+\frac{x}{2}\right),{\left[p\right]}_{i=1,\cdots ,7}=\left[1,2\right]$

12

$\begin{array}{l}{\displaystyle \sum }_{i=1}^8\left\{Y_i\left(1+10\cdot Z_{i+1}\right)\right\}+Y_9\cdot \left(1+10\cdot {\sin }^2\left(\pi \cdot x\right)\right)+Z_1+{\left(\frac{x-1}{4}\right)}^2-c,\\ Y_i={\left({\left[p\right]}_i-1\right)}^2,Z_i={\sin }^2\left(\pi \cdot {\left[p\right]}_i\right),{\left[p\right]}_{i=1,\cdots ,9}=\left[0.9,1.1\right],c=05341615278415\end{array}$