1:if α j 满足(5)和(6)计算 f ( m k + α j δ m ) end
2: if α j 不满足(5) α max = α j , α j = 1 2 ( α min + α max ) 返回步1 end
3:if α j 不满足(6) α min = α j
if α max = 0 , α j = 10 α j else α j = 1 2 ( α min + α max ) end返回步1
end
4: j ← j + 1
end while