变换α的总计数公式

$2^n-4+2P_{n-1}+2T_{1,n-2}{U}_{p+1}^{n-2}+W_{1,n-2}+Q_1$

变换β的总计数公式

$P_{n-1}+3{\displaystyle \sum _{k=1}^{n-2}{C}_{n-1}^k{P}_k}+3\cdot 2^{n-1}-5+2T_{1,n-2}{U}_{p+1}^{n-2}+W_{1,n-2}+Q_2$

总的计数公式

$\begin{array}{l}{2}^n-4+2T_{1,n-2}{U}_{p+1}^{n-2}+W_{1,n-2}+Q_1+P_{n-1}+3{\displaystyle \sum _{k=1}^{n-2}{C}_{n-1}^k{P}_k}+3\cdot 2^{n-1}\\ -5+2T_{1,n-2}{U}_{p+1}^{n-2}+W_{1,n-2}+Q_2\end{array}$