Problem

M

D

TiGE2

ToP

I-DBEA

CCMO

Ours

DC1_DTLZ1

2

6

7.7155e−1 −

1.6343e−1 −

1.0130e−2 +

5.3716e−1 −

7.8894e−2

DC1_DTLZ3

2

11

2.3128e+0 −

1.1296e+0 −

3.7545e−1 −

1.1733e+0 −

3.4909e−1

DC2_DTLZ1

2

6

1.4080e−1 −

NaN −

3.6107e−1 −

8.6613e−2 =

3.9525e−2

DC2_DTLZ3

2

11

5.4186e−1 −

NaN −

9.3103e−1 =

5.0134e−1 −

2.5436e−1

DC3_DTLZ1

2

6

2.3101e+0 −

2.8659e+0 −

1.0849e+0 −

1.2739e+0 −

5.3395e−1

DC3_DTLZ3

2

11

3.7561e+0 −

3.6862e+0 −

2.4646e+0 −

2.0394e+0 −

7.1301e−1

MW1

2

15

1.0984e−1 =

NaN −

4.8522e−1 −

1.1099e−1 =

1.4445e−1

MW2

2

15

4.0653e−2 +

1.9326e−1 =

5.1052e−1 −

1.0975e−1 =

1.2987e−1

MW3

2

15

3.3796e−2 −

6.7104e−1 −

5.0507e−1 −

5.6928e−3 −

5.5625e−3

MW4

3

15

8.4430e−2 =

NaN −

5.2377e−1 −

9.1248e−2 =

9.8783e−2

MW5

2

15

6.8080e−2 =

NaN −

6.5947e−1 −

3.1712e−1 =

3.2222e−1

MW6

2

15

1.8588e−1 +

1.1014e+0 −

7.7884e−1 −

5.1590e−1 =

4.8563e−1

MW7

2

15

4.1996e−2 −

4.8592e−1 −

6.3381e−1 −

6.9709e−3 =

6.7480e−3

MW8

3

15

1.0412e−1 +

9.1731e−1 −

7.9012e−1 −

1.3487e−1 =

1.4839e−1

MW9

2

15

1.4363e−1 =

NaN −

6.5638e−1 −

5.9807e−1 −

4.0667e−1

MW10

2

15

7.9026e−2 +

NaN −

5.3594e−1 −

4.7687e−1 =

3.7931e−1

MW11

2

15

5.0902e−2 −

8.9601e−1 −

1.0904e+0 −

8.5050e−3 −

8.1891e−3

MW12

2

15

1.5637e−1 =

NaN −

7.3341e−1 −

4.4985e−1 =

4.3089e−1

MW13

2

15

4.0789e−1 −

8.4542e−1 −

1.2650e+0 −

2.3922e−1 =

2.6381e−1

MW14

3

15

1.6586e−1 =

3.6381e−1 −

2.7237e+0 −

2.3159e−1 −

1.9394e−1

+/−/=

4/10/6

0/19/1

1/18/1

0/9/11